All categories

3 years ago

Solve S=2(lw + lh + wh) for w

2 answers:

7 0

Dividing by 2, we have S/2=lw+lh+wh. After that, we subtract lh from both sides to get S/2-lh=lw+wh. Next, we divide both sides by w to get (S/2)/w=l+h. Next, we divide by S/2 to get 1/w=(l+h)/(S/2). Lastly, we multiply by w and divide by (l+h)/(S/2) to get w=(S/2)/(l+h)

Nikolay [14]3 years ago

3 0

Answer:

The value of the equation for w is $w=\frac{S-2lh}{2l+2h}$ .

Step-by-step explanation:

Consider the provided equation.

$S=2(lw + lh + wh)$

We need to solve the equation for w.

Distributive property:

$a(b+c)=ab+ac$

Use the above property.

$S=2lw + 2lh + 2wh$

Subtract 2lh from both the sides.

$S-2lh=2lw+ 2wh$

Take w common from the right side.

$S-2lh=w(2l+ 2h)$

Divide both the side by 2l+2h.

$\frac{S-2lh}{2l+2h}=\frac{w(2l+ 2h)}{2l+2h}$

$w=\frac{S-2lh}{2l+2h}$

Hence, the value of the equation for w is $w=\frac{S-2lh}{2l+2h}$ .

You might be interested in

Ron gets $5 on the first day at work, the square of that amount on the second day, and three times the amount of the second day

Ket [755]

Answer:

5 + 25 + 75 = 105 dollars

Step-by-step explanation:

The easiest way is to just take this day by day.

day 1: 5 dollars

day 2: day1^2 = 5^2 = 25

day 3: 3 * day2 = 3 * 25 = 75

Then sum them: 5 + 25 + 75

6 0

3 years ago

A recent study of 200 nurses found that of 125 female nurses, 56 had bachelor's degrees; and of 75

Natasha_Volkova [10]

For the answer to the question above asking about probabilities.
<span>the answer for a) would be 56/200 = 7/25
The answer for
b) would be 75/200 = 3/8 and
lastly the answer for
c)34/200 = 17/100
</span>I hope my answer helped you. Feel free to ask more questions. Have a nice day!

6 0

3 years ago

Read 2 more answers

A 52 card deck of cards is dealt from the top of the deck. what's the probability that it is a red?

Semmy [17]

The probability it is red is 1/2 because there are 2 suits of both red and black making each color have 26 cards so equal amounts equals 1/2

6 0

3 years ago

In quadratic drag problem, the deceleration is proportional to the square of velocity

Mars2501 [29]

Part A

Given that $a= \frac{dv}{dt} =-kv^2$

Then,

$\int dv= -kv^2\int dt \\ \\ \Rightarrow v(t)=-kv^2t+c$

For $v(0)=v_0$ , then

$v(0)=-kv^2(0)+c=v_0 \\ \\ \Rightarrow c=v_0$

Thus, $v(t)=-kv(t)^2t+v_0$

For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

$x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\ \\ =- \frac{1}{2k} + \frac{2}{k} +a$

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

$- \frac{1}{2k} + \frac{2}{k} +a-a \\ \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}$

7 0

3 years ago

Convert the following recipe for 12 portions so that it yields 60 portions.

kiruha [24]

Answer:

15lb chicken 30 oz. soy sauce 5lb. green peppers

2 1/2 lb. scallions 10 oz. ginger

10 cups Water

3 0

3 years ago