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Phoenix [80]
4 years ago
8

Yo I need this as soon as possible

Mathematics
1 answer:
joja [24]4 years ago
3 0

Answer:

Step-by-step explanation:

So, if we know that 25 is the area of the square, that means that each side is 5.  That also means the diameter of the circle is 5, so the radius is 2.5.  Now, we can input the radius into the circumference formula for a circle, which is 2πradius.  So, 2π2.5 which equals 5π, or about 15.71

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Please help? I need the answer quick!
Daniel [21]

Answer:

sorry icant open the picture my phone is lagging

6 0
3 years ago
-4 (y - 2) = 12<br><br> what would “y” be?
OleMash [197]

Answer:

y = -1

Step-by-step explanation:

When solving this equation use the distributive property and get...

-4 (y - 2) = 12

-4y + 8 = 12

-4y = 12 - 8

-4y = 4

y = -1

3 0
3 years ago
What is the answer pleas tell me
tangare [24]

Answer:

i believe its B,C, and E

Step-by-step explanation:

5 0
3 years ago
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
Whoever gets this correct gets brain, 5 stars and a thanks! An explanation of it would be amazing! Tysm!
ivanzaharov [21]
For d and e are correct
I really hope this helps! Have an awesome day:D
3 0
3 years ago
Read 2 more answers
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