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GrogVix [38]
3 years ago
10

Write an equation of a line in slope-intercept form given the slope (m) and the y- intercept (b), slope, m= -4/7 y-intercept b =

7
Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0
The answer is y=-4/7x+7. You simply substitute in the given numbers. -4/7 for the slope (m) and 7 for the y-intercept (b). 
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Answer:

look it up

Step-by-step explanation:

3 0
3 years ago
Adozen of notebooks cost Rs 480. How Much will 7 note book cost? ​
Savatey [412]

Answer: Rs 280

A dozen = 12

12 notebooks --> Rs 480

1 notebooks --> 480/12 =Rs 40

7 notebooks --> 40 * 7 = Rs 280

8 0
3 years ago
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How do I find the percentile of someone with a certain number of things from a dot plot data set?
dalvyx [7]

Answer:

percentile rank of x =

number of values before x                           100

---------------------------------------------------  x    ----------

number of total values on the dot plot         1

Step-by-step explanation:

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5 0
3 years ago
You deposit 2000 in account A, which pays 2.25% annual interest compounded monthly. You deposit another 2000 in account b, which
stellarik [79]
To model this situation, we are going to use the compound interest formula: A=P(1+ \frac{r}{n} )^{nt}
where
A is the final amount after t years 
P is the initial deposit 
r is the interest rate in decimal form 
n is the number of times the interest is compounded per year
t is the time in years 

For account A: 
We know for our problem that P=2000 and r= \frac{2.25}{100} =0.0225. Since the interest is compounded monthly, it is compounded 12 times per year; therefore, n=12. Lets replace those values in our formula:
A=2000(1+ \frac{0.0225}{12} )^{12t}

For account B:
P=2000, r= \frac{3}{100} =0.03, n=12. Lest replace those values in our formula:
A=2000(1+ \frac{0.03}{12} )^{12t}

Since we want to find the time, t, <span>when  the sum of the balance in both accounts is at least 5000, we need to add both accounts and set that sum equal to 5000:
</span>2000(1+ \frac{0.0225}{12} )^{12t}+2000(1+ \frac{0.03}{12} )^{12t}=5000

Now that we have our equation, we just need to solve for t:
2000[(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}]=5000
(1+ \frac{0.0225}{12} )^{12t}+(1+ \frac{0.03}{12} )^{12t}= \frac{5000} {2000}
(1.001875)^{12t}+(1.0025 )^{12t}= \frac{5}&#10;{2}
ln(1.001875)^{12t}+ln(1.0025 )^{12t}=ln( \frac{5} {2})
12tln(1.001875)+12tln(1.0025 )=ln( \frac{5} {2})
t[12ln(1.001875)+12ln(1.0025 )]=ln( \frac{5} {2})
t= \frac{ln( \frac{5}{2} )}{12ln(1.001875)+12ln(1.0025 )}
17.47

We can conclude that after 17.47 years <span>the sum of the balance in both accounts will be at least 5000.</span>
5 0
3 years ago
Estimate how much 10.25 and 30.5
Elza [17]
I don't really get what you are asking for. Can you clarify it?
5 0
3 years ago
Read 2 more answers
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