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Jlenok [28]
2 years ago
15

Solve the inequality. Graph the solution

Mathematics
2 answers:
I am Lyosha [343]2 years ago
6 0

Answer: t≥−12

Step-by-step explanation: 4≥−t/3

4≥−1/3t

(3/−1)(−1/3t)≤(3/−1)(4)

t≥−12

Evgen [1.6K]2 years ago
3 0

Answer:

<em>t ≥ -12 </em>

Step-by-step explanation:

4 ≥ -t/3 Original Equation

4 <em>(3</em>) ≥ -t/3 <em>(3) </em>Cancel out the division

12 ≥ -t

12 <em>(-1)</em> ≥ -t<em> (-1) </em>Canceling Negative on the variable, Flipping over Inequality Sign

<em>t ≥ -12 </em>

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vichka [17]

Answer:

  • B. The probability that the student received a grade better than C is 0.45

Step-by-step explanation:

<u>Total number of students:</u>

  • 15 + 30 + 35 + 16 + 4 = 100
<h3>Statements</h3>

A.

  • p(<D) = 4/100 = 0.04
  • 0.04 ≠ 0.2
  • Incorrect

B.

  • p(>C) = (30 + 15)/100 = 45/100 = 0.45
  • 0.45 = 0.45
  • Correct

C.

  • p(not A or B) = (100 - 15 - 30)/100 = 55/100 = 0.55
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  • Incorrect

D.

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6 0
2 years ago
DAY 27, MAY 7, 2020
KengaRu [80]
If I’m not mistaken, the answer is C.
5 0
3 years ago
Read 2 more answers
7,16,8,27,9 what number continues this pattern
Aloiza [94]
The sequence seems to be that you add 1 and then multiply by 2, and then add 1 and multiply by 3, so I would assume you do 9 + 1 = 10, and then multiply by 4 to get 40 as your next number. I hope this helps!

6 0
3 years ago
What is the range of this data set? {14, 25, 61, 18, 30, 32, 28, 45, 21} 47 28 7 I don't know.
kati45 [8]

The range of the dataset = 47

What is the range of a dataset?

The range of a set of data is the difference between the greatest number and least number

The given data set is:

{14, 25, 61, 18, 30, 32, 28, 45, 21}

The greatest number = 61

The least number = 14

The range of the dataset = Greatest Number - Least Number

The range of the dataset = 61  -  14

The range of the dataset = 47

Learn more on range of a distribution here: brainly.com/question/4679134

3 0
2 years ago
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Help please ! it’s one of the multiple choices
sammy [17]

Answer:

Option C

Step-by-step explanation:

\boxed{Log \ \dfrac{a}{b}=log \ a - log \ b}\\\\\boxed{(log \ a)^b=b*log \ a}

\sf log_w \ \dfrac{(x^{2}-6)^4}{\sqrt[3]{x^2+8} }=log_w \ (x^2-6)^4 - log_w(x^2+8)^{\frac{1}{3}}

                       \sf = 4*log_w \ (x^2 -6) - \dfrac{1}{3}log_w \ (x^2 + 8)

3 0
2 years ago
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