Since they are independent events to find the probability of both is P(A) * P(B)
P(A) = P(Heads) =
P(B) = P(Roll ≥ 4) =
Now multiply those fractions together
= P(Heads & ≥ 4)
Answer: 2 hr.
Explanation: Think back to rate of change. <em>d</em> = <em>rt</em>, <em>r</em> = <em>d/t</em>, <em>t</em> = <em>d/r</em>. In this case, we will be using <em>d</em> = <em>rt</em>. Mph would be <em>r</em>, rate, so you would categorize 15 mph and 8 mph under rate. <em>t</em> should represent the time each cyclist traveled. Tracey's and Emma's distance, <em>d</em>, would be the same as their mph, hence Tracey's being 15<em>t</em> and Emma's would be 8<em>t</em>. When you add Tracey's distance plus Emma's distance, you end up with 46 mi. Now, you need to combine like terms, which should look like 15<em>t</em> + 8<em>t </em> = 46. Add 15 and 8 to get 23, so it should be 23<em>t</em> = 46 now. Then, divide both sides of the equation by 23 and now you should have your answer, <em>t</em> = 2 hr.
The answer is 12/32 i believe.
Answer:
2
Step-by-step explanation:
5-3=2 it's simple really
<u>Answer:</u>
The total number of whole cups that we can fit in the dispenser is 25
<u>Solution:</u>
It is given that the height of each cup is 20 cm.
But when we stack them one on top of the other, they only add a height of 0.8 to the stack.
The stack of cups has to be put in a dispenser of height 30 cm.
So we need o find out how many cups can fit in the dispenser.
Since the first cup is 20 cm high, the height cannot be reduced. So the space to fit in the remaining cups in the stack is only 30-20 cm as that’s the remaining space in the dispenser
So,
30 - 20 = 10 cm
To stack the other cups we have 10 cm of height remaining
As we know that addition of each adds 0.8 cm to the stack, the total number of cups that can be fit in the dispenser can be calculated by the following equation. Let the number of cups other than the first cup be denoted by ‘x’.
10 + 0.8x = 30
0.8x = 20
x = 25
The total number of cups that we can fit in dispenser is 25
