Robin is making bows to sell at her mothers yard sale. She will use 3/4 foot of red ribbon and 2/3 foot of blue ribbon. What is
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Answer:
180
Step-by-step explanation:
First thing to do is to get all the animals in terms of cows, since that is our main unknown. All the other animals' numbers are based on cows. So let's call cows "x". Then sheep is 3 times the number of cows, so sheep is 3x. The number of goats is 45 more than the number of cows, so goats is x + 45. Let's say, for the sake of ease, that the number of animals is "a".
Here's what we have so far:
# of animals: a
# of cows: x
# of sheep: 3x
# of goats: x + 45
We are told that 2/5 of the animals are goats. In an equation, that is:
2/5 (animals) = goats, where the word "of" means to multiply, and the word "are" is the equals sign. Filling in from our key above:
That says that 2/5 of the animals are goats when goats is x + 45.
If 2/5 of the animals are goats, then 3/5 of the animals have to be cows and sheep. In an algebraic equation:
.
Let's go back to the first equation and get rid of the fraction by multiplying everything by 5. When we do that we get
2a = 5(x + 45) so
2a = 5x + 225
Now let's get rid of the fraction in the second equation by multiplying everything by 5. When we do that we get
3a = 5(x + 3x) or
3a = 5(4x) so
3a = 20x. Solve that equation for a.
Now that we have a in terms of x, we can sub that value in for a in the first equation to solve for x, the number of cows:
and, simplifying:
and
. Get rid of the fraction here by multiplying everything by 3:
40x - 15x = 675 and
25x = 675 so
x = 27
That means that there are 27 cows.
Sheep is 3 times that, so there are 81 sheep.
Goats is 45 more than that, so there are 72 goats.
The total number of animals then is 27 + 81 + 72 which is 180. Let's check that to see if the number of goats, 72, is 2/5 of 180.
So we got it! Yay! That was hard!!
The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
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