<span>f(x) =-(x+9)(x-21)
Manipulating algebrically,
We get,
</span>f(x) =-(x+9)(x-21)
= -(x^2 -21x + 9x - 189)
= -(x^2 -12x - 189)
= -x^2 + 12x + 189
Axis of symmetry = -b/2a
plugging the values,
x = -12/-2
= 6
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
Answer:
45 minutes
Step-by-step explanation:
1/2 hour=30 minutes
2/3 of chapter=30 minutes
1/4 of hour=15 minutes
1/3 of chapter=15 minutes
3/4 of hour=45 minutes
3/3 of chapter=45 minutes
TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.
Answer:
well it can be 3 theres many answers
Step-by-step explanation:
3x3x3