T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
96 / 150 = 0.64.
.64 x 100 = 64%
Answer:
It is A' B'
Pls give me brainliest :)
Step-by-step explanation:
Answer: Juanita shoots a series 5 free-throws. Let M = the number of free-throws she makes.
Step-by-step explanation: Khan
Answer: $13,846.02
Step-by-step explanation:
The car cost $29,750 when it was first bought.
It will then depreciate at a rate of 12% per year. This means that the value of the car reduces by 12% per year.
To find the value of the car in the 6th year, you can use the compound interest formula:
= Value of car * ( 1 - rate) ^ no. of years
= 29,750 * ( 1 - 12%)⁶
= 13,816.021581824
= $13,846.02
