See below for the terms, coefficients, and constants in the variable expressions
<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>
To determine the terms, coefficients, and constants, we use the following instance:
ax + by + c
Where the variables are x and y
- Then the terms are ax, by and c
- The coefficients are a and b
- The constant is c
Using the above as guide, we have:
A) 2b + 2ac+5
- Terms: 2b, 2ac, 5
- Coefficient: 2, 2 and 5
- Constant 5
B) 34abx + 16y +1
- Terms: 34abx, 16y, 1
- Coefficient: 34ab, 16
- Constant: 1
C) st +4u + v
- Terms: st, 4u, v
- Coefficient: 4
D) 14xy + 6
- Terms: 14xy, 6
- Coefficient: 14, 6
- Constant 6
E) 14x + 12y
- Terms: 14x, 12y
- Coefficient: 14, 12
F) 3+ 6-7+a
- Terms: 3, 6, -7, a
- Coefficient: 1
- Constant: 3, 6, -7
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Answer
455
Step-by-step explanation:
(1×1) + 1 = 2
(2×2) + 2 = 6
(6×3) + 3 = 21
(21×4)+4 = 88
(88×5)+5 = 445
Answer:
The maximum number of quarters that he could have is 13
Step-by-step explanation:
Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then
→ x + 10 >= 20
→ x >= 10 (1)
His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.
→ (x * 25) + (10 * 10) <= (4.25 * 100)
→ 25x + 100 <= 425
→ 25x <= 325
→ x <= 13 (2)
If we combine the equation 1 and 2:
10 <= x <= 13
The maximum value of x is 13
Answer:
15 years old
Step-by-step explanation:
Start by defining the variables that we are going to use throughout our working:
Let the current age of Wei Ling and Wei Xuan be L and X years old respectively.
Next, form equations using the given information.
<u>5 years </u><u>ago</u>
Wei Ling: (L -5) years old
Wei Xuan: (X -5) years old
Given that the ratio of Wei Ling's age to that of Wei Xuan's is 2: 5,
Cross multiply:
2(X -5)= 5(L -5)
Expand:
2X -10= 5L -25
2X= 5L -25 +10
2X= 5L -15 -----(1)
<u>9 years time</u>
Wei Ling: (L +9) years old
Wei Xuan: (X +9) years old
Given that the ratio of Wei Ling's age to that of Wei Xuan is 3: 4,
Cross multiply:
3(X +9)= 4(L +9)
Expand:
3X +27= 4L +36
3X= 4L +36 -27
3X= 4L +9 -----(2)
Let's solve using the elimination method.
(1) ×3:
6X= 15L -45 -----(3)
(2) ×2:
6X= 8L +18 -----(4)
(3) -(4):
6X -6X= 15L -45 -(8L +18)
0= 15L -45 -8L -18
0= 7L -63
7L= 63
L= 63 ÷7
L= 9
Substitute L= 9 into (1):
2X= 5(9) -15
2X= 45 -15
2X= 30
X= 30 ÷2
X= 15
Thus, Wei Xuan is 15 years old now.
Answer:
Step-by-step explanation:
1) 
is in exponential form.
<u>Now, radical form is </u>![\sqrt[3]{5^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E%7B2%7D%20%7D)
2) 
is in exponential form.
<u>Radical form is </u>
3) 
is in exponential form.
<u> Radical form is </u>![\sqrt[5]{3^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B3%5E%7B2%7D%20%7D)
4) 
is in exponential form.
<u> Radical form is </u>
<h3>
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