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PSYCHO15rus [73]
3 years ago
8

8-2w=6w-8 help lol!!!!!!!!!!!

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
5 0
W = 2. How do we find this out?

Put "w" as "2". 8-2(2)=6(2)-8
8 - 4 = 12 - 8.

Solve.

4 = 4

Hope this helps! ☺♥
Nimfa-mama [501]3 years ago
5 0
8 = 6w - 8 + 2w
8 = 8w - 8
8 + 8 = 8w
16 = 8w
w = 16/8
w = 2
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g(x)=5cos((\pi )/(2)x-(3\pi )/(2))-2

generate by:  Amplitude:5    Period:4

                      Phase shift:(3 to the right)    Vertical shift:-2

x=3,g(x)= 3

x=4,g(x)= -2

x=5,g(x)= -5

x=6,g(x)= -2

x=7,g(x)= 3

the graph is like cos(x)

learn more about trigonometric graphs here:

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3 0
1 year ago
T3=-6.5 and t5=-3.9 determine d
nekit [7.7K]
t_3=-6.5;\ t_5=-3.9\\\\t_5-t_3=2d\\\\2d=-3.9-(-6.5)\\\\2d=-3.9+6.5\\\\2d=2.6\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{d=1.3}
4 0
3 years ago
A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.
balandron [24]

The cyclic quadrilateral's opposing angles are 180 degrees, which become supplementary angles.

<h3>What is a cyclic quadrilateral?</h3>

If the quadrilateral is inscribed in a circle then the quadrilateral is known as a cyclic quadrilateral.

A quadrilateral can be inscribed in a circle, if and only if, the opposite angles in that quadrilateral are supplementary.

We know that the sum of the opposite angles of the cyclic quadrilateral is equal to 180 degrees.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

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4 0
2 years ago
Solve y In terms of x
miss Akunina [59]

the answer is y=3x-6

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divide both sides by -2y → y=3x-6


4 0
3 years ago
Read 2 more answers
Logx(8x-3)-logx 4=2<br> please help ill give you everything i have !!
Gelneren [198K]
Logx (8x-3) - logx 4 = 2
logx [(8x-3)/4] = 2
x^2=(8x-3)/4
4x^2=4(8x-3)/4
4x^2=8x-3
4x^2-8x+3=8x-3-8x+3
4x^2-8x+3=0
4(4x^2-8x+3=0)
(4^2)(x^2)-8(4x)+12=0
(4x)^2-8(4x)+12=0
(4x-2)(4x-6)=0
2(4x/2-2/2)2(4x/2-6/2)=0
4(2x-1)(2x-3)=0
4(2x-1)(2x-3)/4=0/4
(2x-1)(2x-3)=0
Two options:
1) 2x-1=0
2x-1+1=0+1
2x=1
2x/2=1/2
x=1/2

2) 2x-3=0
2x-3+3=0+3
2x=3
2x/2=3/2
x=3/2

Answer: Two solutions: x=1/2 and x=3/2
6 0
3 years ago
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