Answer:
170 in^2
Step-by-step explanation:
you have to find the area of each surface of the square
1) the square on the right side:
5x5=25 in^2
there are 2 of these on opposite sides
2)the of the rectangle facing us;
6x5=30in^2 (5 because 5 is the height)
there are 4 of these
3)add up all the areas
25+25+30+30+30+30=170in^2
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
9514 1404 393
Answer:
Step-by-step explanation:
There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.
Let m = 0i +1j +ak. Then we require ...
m·p = 0 = 0×1 +1×2 +a(-2) ⇒ 0 = 2 -2a ⇒ a = 1
m = 0i +1j +1k
__
Let n = 2i +0j +bk
n·p = 0 = 2×1 +0×2 +b(-2) ⇒ 2 -2b = 0 ⇒ b = 1
n = 2i +0j +1k
So first we assume that half is adult and have is student.
So
215 adult 215 student
Now since it said they were 70 less student tickets than adult tickets we subtract 70.
215 - 70 = 145
Now we add the 70 we subtracted from student tickets to the adult tickets.
215 + 70 = 285
So there were
285 adult tickets sold and 145 student tickets sold
I hope this helped. Have a great day!
