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3 years ago

How to graph this inequality on a number line? -7 is less than or equal to x less than or equal to 4

Mathematics

1 answer:

defon3 years ago

3 0

-7 < = x < = 4

closed circles on -7 and 4 (because of the equal signs). and shading in between.

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3 years ago

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vazorg [7]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

This table shows the number of customers who have come in to Trent’s Hobby Shop each day since he opened the doors.

Alona [7]

Since both the input and the output assume only integer values, the function is classified as discrete.

<h3>What are continuous and discrete variables?</h3>

Continuous variables: Can assume decimal values, hence they are represented by rational numbers.

Discrete variables: Assume only countable values, such as 1, 2, 3, …, hence they are represented by whole numbers, or even integers if it can be negative.

In this problem, all values on the table assume only integer values, hence the function is classified as discrete.

More can be learned about classification of variables at brainly.com/question/16978770

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2 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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3 years ago