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Slav-nsk [51]
3 years ago
8

What is the extracts volume of the largest cone that can fit into a cube with edges of 10 inches

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
Volume of a cone = π r² h/3

I envisioned a cone inside a cube. I only identified the necessary value to compute for the exact volume of the largest cone.

Edges of the cube is 10 inches. When the circle part of the cone is placed in the circle, the diameter would be 10 inches also. I divided it by 2 to get the value of the radius, resulting to 5 inches.

The height of the cone is also the height of the cube. Thus, it is 10 inches.

Volume of the cone = 3.14 * (5in)² * 10in/3
V = 3.14 * 25in² * 3.33 in
V = 261.405 in³ or 261.41 in³  VOLUME OF THE LARGEST CONE THAT CAN FIT IN A 10 INCH CUBE

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slega [8]
Y is greater than or equal to 5. It says no less than, making the equal to possible.
6 0
3 years ago
Please please please help help help help help!!!!!!!!!!!!!
Feliz [49]

Answer:

15 and 108

Step-by-step explanation:

3*(30-25)=3*5=15

4*(12+15)=4*27=108

5 0
3 years ago
Can someone plz help me with this one problem!!!
Ymorist [56]
No i believe but I’m unsure
4 0
3 years ago
Read 2 more answers
Given is a finite set of spherical planets, all of the same radius and no two intersecting. On the surface of each planet consid
wariber [46]

Answer:

Step-by-step explanation:

To answer this question, First, we define a direction in space, which defines

the North Pole of each planet.

We also assume that the direction is not at 90° perpendicular to the axis of any two planet.

Assume we now define an order on the set of planet by saying that planet A ≥ B, when removing all the other planet from space, the north pole B, is visible from A.

If we refer to the direction of the planet in the diagram, we discover that,

1, A ≥ A

2, If A ≥ B and B≥ A,

Then A = B

3, If A ≥ B, and B ≥ C , then A ≥ C

4, Either A ≥ B or B ≥ A

It should also be noted that the array of order above has a unique maximal element  (M). This is the only  planet whose North Pole is not visible from another.

If we now consider a sphere of the same radius as the planets. Remove

from it all North Poles defined by directions that are perpendicular

to the axis of two of the planets. This is a set of area zero.

For every other point on this sphere, there exists a direction in

space that makes it the North Pole, and for that direction, there

exists a unique North Pole on one of the planets which is not visible

from the others. Hence the total area of invisible points is equal

to the area of this sphere, which in turn is the area of one of the  planets.

5 0
3 years ago
Total crimes 21,790,654. Roberry is 408, 016 and Burglary is 2,050,992 What are their percent in crimes rounded to the nearest p
RSB [31]

Answer:

Percent of Robbery =2 \%

Percent of Robbery =9 \%

Step-by-step explanation:

Given that total number of crimes = 21,790,654.

total number of Robbery = 408, 016 and

total number of Burglary = 2,050,992

Now we need to find about what are their percent in crimes rounded to the nearest percent for each two crimes.

So apply the percent formula

Percent=\frac{Part}{Whole}\times 100 \%

Then percent of Robbery =\frac{408016}{21790654}\times 100 \%=0.01872\times 100 \%=2 \%

Then percent of Robbery =\frac{2050992}{21790654}\times 100 \%=0.094122\times 100 \%=9 \%

8 0
3 years ago
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