The chemical reaction of magnesium and sodium hydroxide would yield magnesium hydroxide and sodium. The chemical reaction is expressed as:
Mg(s)+ 2NaOH(aq)→Mg(OH)2(s)+2Na
In ionic form,
Mg(s) + 2Na+ + 2OH−(aq)→Mg(OH)2(s) + 2Na
Answer:
5.9405*10^14 Hz
Explanation:
Remember the equation c=v*λ
v=frequency
λ=wavelength
By manipulating the equation, we can get it in terms of frequency:
c/λ=v
Now convert wavelength to meters (1nm=m*10^-9)
5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)
Use the manipulated equation:
(3.00*10^8)/(5.05*10^-7), which yields:
5.9405*10^14 Hz (or s^-1)
Answer:
it's a covalent compound
Explanation:
Two non metals are bonded to together
37.5 for median ( first organize from least to greatest, elimate from each side until you get to center then add two numbers and divide by two.) Hope that helps.
Answer:
Theoretical yield of sodium chloride = 14.04 g
Explanation:
Given data:
Mass of sodium bromide = 25 g
Theoretical yield of sodium chloride = ?
Solution:
Chemical equation:
NaBr + KCl → NaCl + KBr
Number of moles sodium bromide:
Number of moles = Mass /molar mass
Number of moles = 25.0 g / 102.9 g/mol
Number of moles = 0.24 mol
Now we will compare the moles of NaCl with NaBr .
NaBr : NaCl
1 : 1
0.24 : 0.24
Theoretical yield of sodium chloride:
Mass = moles × molar mass
Mass = 0.24 mol × 58.5 g/mol
Mass = 14.04 g