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V125BC [204]
2 years ago
11

The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).

Chemistry
1 answer:
Kitty [74]2 years ago
6 0

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

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IgorLugansk [536]

Answer:

Silicon tetrachloride

Explanation:

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3 years ago
A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called
grandymaker [24]
Answer:
             <span>A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called <em>cis</em> Isomer.

Explanation:
                   Geometric isomerism takes place about the double bond in alkenes when the alkyl groups are either situated at the same side (<em>cis</em>) or are situated opposite (<em>trans</em>) to each other.

Example:
               <em>cis</em>-2-Butene (highlighted red)

               <em>trans</em>-2-Butene (highlighted blue)</span>

5 0
3 years ago
What is the pH of a solution which is 0.600 M in dimethylamine ((CH3)2NH) and 0.400 M in dimethylamine hydrochloride ((CH3)2NH2C
Viefleur [7K]

Answer:

pH = 11.05

Explanation:

It is possible to answer this question using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A] / [HA⁺]

Where A in this case is weak base (dimethylamine) and conjugate acid (HA⁺) is dimethylamine hydrochloride.

As Ka= Kw / Kb = 1x10⁻¹⁴ / 7.4x10⁻⁴ = 1.35x10⁻¹¹ And pKa is -log Ka = <em>10.87 </em> pH of the solution is:

pH = 10.87 + log₁₀ [0.600] / [0.400]

<em>pH = 11.05</em>

<em></em>

I hope it helps!

3 0
3 years ago
2. The Density of Water is 1.0000g/cm3. Based on this property of water,
Vanyuwa [196]

Answer:

if the object sank then that object has a greater density then water. if the object floated then its density is lower then water.

Explanation:

lets say object 1 has a density of 24/cm3. the density is greater then water (1.0000g/cm3) so it would sink. now lets say object 2 has a density of 0.79383g/cm3 since it's less then the density of water (1.0000g/cm3) it would float.

7 0
3 years ago
if 2.22 moles of ammonia (NH3) decomposes according to the reaction shown how many moles of hydrogen (H2) are formed?
kirill [66]

Answer:

five(5) hydrogen are formed

6 0
2 years ago
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