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V125BC [204]
2 years ago
11

The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).

Chemistry
1 answer:
Kitty [74]2 years ago
6 0

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

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2.79 mg iron-59 is left in the sample after 267 days.

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So,  

[A_t]=180\ mg\times e^{-0.0156\times 267}

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[A_t]=2.79\ mg

<u>2.79 mg iron-59 is left in the sample after 267 days.</u>

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Above question is incomplete. Complete question is attached below
.......................................................................................................................

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Reason:
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