1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
melamori03 [73]
3 years ago
15

The picture that graphically represents the items you use in windows is called a/an

Computers and Technology
2 answers:
Kitty [74]3 years ago
6 0
The picture that graphically represents the items you use in windows is called "icon"

Marizza181 [45]3 years ago
4 0
The picture that represents the items or programs is called a icon, you can change the icon or delete it
You might be interested in
what occurs when two adjacent conductors make electrical contact and by-pass a portion of the circuit?
Naily [24]
Its  a short circuit.
5 0
3 years ago
Emilee is watching an online video. The video is being sent to her laptop by a server over the Internet which splits the video i
Tresset [83]

Answer:

The answer is "Option C".

Explanation:The packet includes clients and modifies information both of these are often referred to as the payload. To achieve payload data by monitor data to get the control signals. It is a unit that will be an information material consisting of a specific network path into such a single packet and web browser transmissions and other types of networks will be used in the IP transmissions, in this, the data packet may arrive in out of order, and the wrong choice can be defined as follows:

  • In choice A, when the connection is good so, all the data is sent on the computer, that's why it is incorrect.
  • In choice B, It is wrong because it can't send back to the server.
  • In choice D, It can't be sent in order, that's why it is wrong.  
6 0
4 years ago
Data Structure in C++
agasfer [191]

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

   

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

   

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

   

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

4 0
4 years ago
The ideal light to use is?
alekssr [168]

Answer:

i think that the idea light to use is a front light?

it can lighten a dark room depending on the radius of the light or the refletor, im not sure if this is 100% right but i hope this helps you in some way!

×║hope this helps!║×

6 0
3 years ago
Suppose list1 is an MyArrayList and list2 is a MyLinkedList. Both contains 1 million double values. Analyze the following code:
hjlf

Answer:

The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".

Explanation:

In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below

(A.) The Code fragment A runs fastly than the code fragment of B.

(B.) The Code fragment B runs fastly than code fragment of  A.

(C)  The Code fragment A runs as fastly as code fragment of B.  

So we conclude the answer i.e option(A) because As given in the question list1  is a MyArrayList and list2 is a MyLinkedList.  , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.

The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then  MyArrayList is a better option so the code fragment runs fastly then code fragmented B.

7 0
4 years ago
Other questions:
  • Anna is looking for a job. Which two types of skills would she find necessary to secure a job?
    10·1 answer
  • With the technology scaling and process improvement, do you think that existing CMOS will be able to exist in future?
    6·1 answer
  • The most significant factor in choosing a transmission method is its ____.
    10·1 answer
  • Leonardo is having difficulty accessing the course website. he should contact the for assistance. (points:1)
    13·1 answer
  • The combined resistance of three resistors in parallel is: Rt = 1 / ( 1 / r 1 + 1 / r 2 + 1 / r 3 ) Create a variable for each o
    15·1 answer
  • Consider a file currently consisting of 100 blocks. Assume that the file control block (and the index block, in the case of inde
    12·1 answer
  • Which of the following could NOT be represented by a boolean variable?
    8·1 answer
  • Guyssss......urgent helppp plsss answerrrr
    5·1 answer
  • What are possible consequences for cyberbullying?
    13·2 answers
  • window operating system popularly known as. 1) character user interface. 2) computer user interface. 3) graphic user interface.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!