The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement.
A
C
B
Since m∠A = 22º is given, we know m∠B = 68º since there are 180º in the triangle. Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A.
If we write, m∠B = 90º - m∠A (or m∠A = 90º - m∠B ), and we substitute into the original observation, we have:
Not quite sure what you mean by brackets, but you can get the solution to this equation in a few steps:
<span>(-2x - 1)</span>² <span>= 0 ... square root both sides to eliminate the squared binomial
</span>√(-2x - 1)² = √0 ... simplify; the square is canceled out and the root of 0 brings you back to 0
-2x - 1 = 0 ... solve like a two-step equation
-2x = 1
x = -1/2 is your x-value.
Answer: <em><u>Reflection</u></em>
Step-by-step explanation:<em> reflection: when a figure flips over a line</em>
<em />
27, you subtract 34-7 and you get 27
