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svet-max [94.6K]
2 years ago
10

suppose you earn $6 per hour at your pat-time job. what will your new hourly rate be afer a 2.5% rise? Explain

Mathematics
2 answers:
kiruha [24]2 years ago
7 0
The person explained fully
lbvjy [14]2 years ago
4 0

For 2.5% rise we first find increase and then add it to 6

Increase = 2.5% of 6 = 2.5/100 × 6= 15/100 =0.15$

New rates = $(6+0.15) = $6.15

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At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m
Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

  • Almost all the data lies within three standard deviation from the mean for a normally distributed data.
  • About 68% of data lies within one standard deviation from the mean.
  • About 95% of data lies within two standard deviations of the mean.
  • About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30

Thus, 99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

3 0
3 years ago
Hey guys can you answer this one question real quick
Umnica [9.8K]

Answer:

a. 1/5

b. (3, 3/5)

c. 1/5x = y

Step-by-step explanation:

Remember: (x, y)

0.5 = 1/2

(1/2, 1/10) = 1/10 ÷ 1/2 = 1/10 • 2 = 1/5, you can divide y/x = constant of proportionality. 1/10 ÷ 1/2.

1 2/5 = 7/5

(7, 7/5) = 7/5 ÷ 7 = 7/5 • 1/7 = 1/5, y/x = constant of proportionality. 7/5 ÷ 7.

  • a. 1/5 is the constant of proportionality
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6 0
3 years ago
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Paladinen [302]

Answer: k=-1/x^2+2

         

Step-by-step explanation:

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3 years ago
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Of 960 pages 384 had an add. What's the probability it contains an add
kramer
384/960
Thus, answer=2/5
4 0
3 years ago
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