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4 years ago

15

on a map, the distance between Sheila's house and shardae's house is 6.75 inches. according to the scale, 1.5 inches represents

5 miles. how far apart are the houses?

1 answer:

steposvetlana [31]4 years ago

7 0

I believe 22.5 miles! Hope this helps!

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Give 3 angle measures of an obtuse triangle.

MaRussiya [10]

Answer:There are many different answers :-) but 100, 40, 40 is one

Step-by-step explanation:

There are quite a few answers, but you need to make sure 1 angle is greater than 90 degrees. The remaining two angles should add up to less than 89 degrees and all 3 angles should total 180 degrees.

i.e. 100, 40, 40

8 0

4 years ago

Log5(x-1)+log5(x+3)-1=0

jonny [76]

Answer:

there are no real solutions

Step-by-step explanation:

$\log_5(x-1)+\log_5(x+3)-1=0\\\\\log_5(x-1)+\log_5(x+3)=1$

there is a rule that says

$\log_b(a)+\log_b(c)=\log_b(ac)$

so we have

$\log_5(x-1)+\log_5(x+3)=\log_5((x-1)(x+3))=1$

and we have the definition

$\log_a(b)=c\\\\a^{c} =b$

so we have

$5^{1} = (x-1)(x+3)\\\\5=x^{2} -1x+3x-3\\\\5=x^{2} +2x-3\\\\0=x^{2} +2x-3-5\\\\0=x^{2} +2x-8\\\\$

and using the quadratic formula we get that

there are no real solutions

3 0

3 years ago

Read 2 more answers

What substitution should be used to rewrite 6(x 5)2 5(x 5) – 4 = 0 as a quadratic equation? u = (x 5) u = (x – 5) u = (x 5)2 u =

Korolek [52]

The substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5

<h3>Quadratic equations</h3>

These are equations that has a leading degree of 2. Given the expression

6(x+5)^2 + 5(x+5) - 4 = 0

In order to simplify this equation, we will replace the reoccuring term by a variable.

From the equation we can see that (x+5) is occuring the most. Let u = x + 5 so that:

6u^2 - 5u - 4 = 0

Hence the substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5

Learn more on quadratic equation here: brainly.com/question/1214333

#SPJ4

4 0

2 years ago

A ball is thrown from a height of 44 meters with an initial downward velocity of 6 m/s . The ball's height h (in meters) after t

goblinko [34]

Answer:

Step-by-step explanation:

h = -5t^2 - 6t + 44

I'll assume 0 meters is the ground height. That would mean we want to know the time, t, for h to be = 0 meters:

h = -5t^2 - 6t + 44

0 = -5t^2 - 6t + 44

5t^2 + 6t -44 = 0

Solve using the quadratic equation: 2.43 and - 3.63 seconds. We'll use the positive value: 2.43 seconds for the ball to reach the ground. Save the -3.63 value for the Klingons.

We can also solve by graphing the function, as per the attached image. Note that the starting time of 0 seconds, the ball is at 44 feet. It reaches the x axis at 2.43 seconds (where x = 0, the ground).

7 0

3 years ago

Read 2 more answers

Plz help solve this please and thx u<br><br>

kow [346]

2 (an - 1) = 40
2an - 2 =40
2an = 40 - 2
2an = 38
2an/2 = 38/2
an = 19

3 0

3 years ago