Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Answer:
4√3 according to khan academy
Step-by-step explanation:
Answer:
about 37.7 feet
Step-by-step explanation:
If the outside wheels are turning twice as fast, they go twice the distance in the same time. The distance they travel is proportional to the radius of the circle, so the outside circle must have twice the radius of the inside circle.
Adding 6 ft to the radius of the inside circle doubles the radius, so the inside circle's radius must be 6 feet. Then the circumference of the inside circle is ...
C = 2πr = 2π(6 ft) = 12π ft ≈ 37.7 ft
The answer is 86.4 I believe.
-0.5,-0.4,-0.3,-0.1,0,1,2,3,4,4.17
