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babymother [125]

2 years ago

13

When we reject the null hypothesis, we would expect the variance ratio, over the long run, to be:_________

1 answer:

FinnZ [79.3K]2 years ago

5 0

Answer:

Cuando rechazamos la hipótesis nula, esperaríamos que la razón de varianza, a largo plazo, sea: <u>mayor al valor crítico.</u>

Step-by-step explanation:

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The following data are the distances between 20 retail stores and a large distribution center. The distances are in miles.

Free_Kalibri [48]

Answer:

1191.4 ; 34.5

Step-by-step explanation:

Given the data:

29; 37; 38; 40; 58; 67; 68; 69; 76; 86; 87; 95; 96; 96; 99; 106; 112; 127; 145; 150

The sample variance and standard deviation can be obtained thus :

Σ(X - m)² / (n - 1)

Where, m = mean of the sample

n = sample size

The standard deviation equals, sqrt(variance )

Using a calculator:

The variance, σ² ;

Mean = Σx / n = 1681 / 20 = 84.05

(x -m)^2

[(29-84.05)^2 + (37-84.05)^2 + (38-84.05)^2 + (40-84.05)^2 + (58-84.05)^2 + (67-84.05)^2 + (68-84.05)^2 + (69-84.05)^2 + (76-84.05)^2 + (86-84.05)^2 + (87-84.05)^2 + (95-84.05)^2 + (96-84.05)^2 + (96-84.05)^2 + (99-84.05)^2 + (106-84.05)^2 + (112-84.05)^2 + (127-84.05)^2 + (145-84.05)^2 + (150-84.05)^2] / 19

22636.95 / 19

= 1191.4184 = 1191.42

Standard deviation = sqrt( Variance)

Standard deviation = sqrt(1191.4184)

Standard deviation = 34.516929 = 34.52

4 0

2 years ago

What is the value of x? Enter your answer in the box. mm Triangle V T K with segment T Y such that Y is on segment V K, between

lapo4ka [179]

Answer:

VK = x = 98 mm

Step-by-step explanation:

TY is the bisector of angle T, so it divides segments of the triangle proportionally. That is, ...

VY/VT = KY/KT

VY = VT·KY/KT = (57 mm)·68/192.2 = 30 mm

Then

VK = VY + YK = 30 mm + 68 mm

VK = 98 mm

5 0

2 years ago

Read 2 more answers

Which function has the graph shown?

Alexeev081 [22]

Answer:

B

Step-by-step explanation:

The graph is a sine curve but multiplied by -1

7 0

2 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago

5 * 10^6 is how many times larger as 5 * 10^4

Alexxandr [17]

$\dfrac{5\cdot10^6}{5\cdot10^4}=10^{6-4}=10^2=100$

7 0

2 years ago

Read 2 more answers