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Daniel [21]
2 years ago
10

Match the equivalent expressions 3x+5x+8, 4x+4x, 4x+4x+4x+4x, -7x + 4 + 3x, 8x, 16x, -4x + 4 and 8x + 8

Mathematics
1 answer:
FrozenT [24]2 years ago
4 0

Answer:

Combine like terms; 3x + 5x= 8x

Since you don't have any like terms for +8, it's going to remain the same and not change.

Answer : 3x + 5x + 8 = 8x + 8

Again with combining like terms, 4x + 4x = 8x  

Answer: 4x + 4x = 8x

The third expression is going to be very similar to the last problem. 4x + 4x + 4x + 4x. We're going to add the terms together. 4+4+4+4 is equal to 16. Bring the x down and you get...

Answer: 16x

Lastly, we have -7x + 4 + 3x. Do the exact same thing we did to the other problems, combining like terms, shocking, I know. -7x + 3x= -4 and since there's no other like terms for +4, it stays the same. Therefore

Answer: -7x + 4 + 3x = -4 + 4

I hope this helps, mark as brainliest, please? :)

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\text{We have }\ 2\dfrac{1}{3},\ h,\ k,\ 7\dfrac{7}{8}.\\\\\text{Convert the mixed numbers to the improper fractions}\\\\2\dfrac{1}{3}=\dfrac{2\cdot3+1}{3}=\dfrac{7}{3}\\\\7\dfrac{7}{8}=\dfrac{7\cdot8+7}{8}=\dfrac{63}{8}\\\\\text{If}\ a_1,\ a_2,\ a_3,\ a_4\ \text{is a geometric seqence, then:}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=r\\\\a_2=a_1r\\\\\text{and}\ \dfrac{a_4}{a_1}=r^3\\\\\text{Substitute:}

r^3=\dfrac{\frac{63}{8}}{\frac{7}{3}}\\\\r^3=\dfrac{63}{8}\cdot\dfrac{3}{7}\\\\r^3=\dfrac{9\cdot3}{8\cdot1}\\\\r^3=\dfrac{27}{8}\to r=\sqrt[3]{\dfrac{27}{8}}\\\\r=\dfrac{3}{2}\\\\h=2\dfrac{1}{3}\cdot\dfrac{3}{2}=\dfrac{7}{3}\cdot\dfrac{3}{2}=\dfrac{7}{2}\\\\k=\dfrac{7}{2}\cdot\dfrac{3}{2}=\dfrac{21}{4}\\\\Answer:\ \boxed{h=\dfrac{7}{2}=3\dfrac{1}{2}\ and\ k=\dfrac{21}{4}=5\dfrac{1}{4}}

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