Answer: No, is this the question?
Explanation: Have a stupendous day! <3
Answer:
Time taken to travel from one track to the next = 0.08ms
Initial track= 15 0
4 (15-4)*(0.08)= 0.88
40 (40-4)*(0.08)= 2.88
35 (40-35)*(0.08)= 0.4
11 (35-11)*(0.08)= 1.92
14 (14-11)*(0.08)= 0.24
7 (14-7)*(0.08)= 0.56
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Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms
Explanation:
We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.
I believe the answer is C.
Answer:
hardware-initiated reset
Explanation:
Once in protected mode, the 80286 is designed to remain there until it is reset by hardware.
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External hardware can be designed so that software can cause such a reset. In the 1984 PC/AT, such hardware combined with code in the BIOS allowed real mode re-entry and returned execution control to the program that caused the reset.
Answer:
Yes, all you do is click 'share' on the top right and then copy the link, then you would send the link to said to person that has a icloud email.
