All categories

3 years ago

23

Mathematics

1 answer:

denpristay [2]3 years ago

5 0

Answer:

Actual height of the building is 670 m

Step-by-step explanation:

We have been the actual height of a Ferris wheel which is 134 m. Along with it we are also given the scaled down heights of a Ferris wheel and a building. Using this data we have to find the actual height of a building.

Actual height of Ferris wheel = 134 m.

Height of Ferris wheel using the scale = 0.65 cm

Height of building after using the scale - 3.25 cm

Let, the actual height of building be x meters.

Since, the same scale is being used, the ratio of actual heights to that of scaled down heights must be the same for both objects.

i.e.

Ratio of Actual Height to scale height of Ferris Wheel = Ratio of Actual Height to scale height of the building

Using the values, we get:

$134:0.65 =x:3.25\\\\\frac{134}{0.65}=\frac{x}{3.25}\\\\ \frac{134}{0.65} \times 3.25 = x\\\\ x=670$

The units of actual heights are in meters, so this means the actual height of the building is 670 m

You might be interested in

Bobby is testing the effectiveness of a new cough medication. There are 100 people with a cough in the study. Seventy patients r

Tresset [83]

Answer:

0.665

Step-by-step explanation:

Given: 100 people are split into two groups 70 and 30. I group is given cough syrup treatment but second group did not.

Prob for a person to be in the cough medication group = 0.70

Out of people who received medication, 34% did not have cough

Prob for a person to be in cough medication and did not have cough

= $\frac{0.70(34)}{60}=0.397$

Prob for a person to be not in cough medication and did not have cough

= $\frac{0.3(20)}{30}=0.20$

Probability for a person not to have cough

= P(M1C')+P(M2C')

where M1 = event of having medication and M2 = not having medication and C' not having cough

This is because M1 and M2 are mutually exclusive and exhaustive

SO P(C') = 0.397+0.2=0.597

Hence required prob =P(M1/C') = $\frac{0.397}{0.597}=0.665$

4 0

3 years ago

Read 2 more answers

“7a - 17 = 4a +1”<br><br> Step by step pls

Monica [59]

Answer:

a = 6

Step-by-step explanation:

7a-17 = 4a +1 ; Subtract 4a from both sides

3a - 17 = 1 ; Add 17 to both sides

3a = 18 ; Divide both sides by 3

a = 6

6 0

3 years ago

Read 2 more answers

Whats 21/35. simplified

Tems11 [23]

3/5 is 21/35 simplified

4 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

Find the surface area please

True [87]

Answer:

150 ft

Step-by-step explanation:

5 0

3 years ago