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3 years ago

A height of 26 feet and a diameter of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?

Mathematics

1 answer:

7nadin3 [17]3 years ago

8 0

Answer:

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

Step-by-step explanation:

Given:

Geode shaped approximately like a cylinder. such that

Height = h = 26 feet

Diameter = d = 5.6 feet

$Radius = r =\dfrac{d}{2}=\dfrac{5.6}{2}=2.8\ feet$

To Find:

volume of the geode = ?

Solution:

Geode shaped approximately like a cylinder,

So, Volume of Cylinder is given by,

$\textrm{Volume of Cylinder}=\pi r^{2}h$

Where,

Height = h

Radius = r

pi = 3.14

Substituting the values we get

$\textrm{Volume of Cylinder}=3.14\times 2.8^{2}\times 26=640.05\approx 640.1\ feet^{3}$

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

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3 years ago

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2 years ago

) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi

wolverine [178]

Answer:

This code or is program to find a given value of derivative of a polynomial.

Step-by-step explanation:

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#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

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float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

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printf("Enter the coefficient of x to the power %d: ",i);

scanf("%f",&a[i]);

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/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

p = a[deg];

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3 years ago

Find the fourth-degree polynomial function with zeros 4, -4, 4i , and -4i . Write the function in factored form.

Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .

To find:

The fourth-degree polynomial function in factored form.

Solution:

The factor for of nth degree polynomial is:

$P(x)=(x-a_1)(x-a_2)...(x-a_n)$

Where, $a_1,a_2,...,a_n$ are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:

$P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))$

$P(x)=(x-4)(x+4)(x-4i)(x+4i)$

$P(x)=(x-4)(x+4)(x^2-(4i)^2)$ $[\because a^2-b^2=(a-b)(a+b)]$

On further simplification, we get

$P(x)=(x-4)(x+4)(x^2-4^2i^2)$

$P(x)=(x-4)(x+4)(x^2+16)$ $[\because i^2=-1]$

Therefore, the required fourth degree polynomial is $P(x)=(x-4)(x+4)(x^2+16)$ .

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2 years ago