Question

A height of 26 feet and a diameter of 5.6 feet. What is the volume of the geode, rounded to the nearest tenth?

Answer 1

Answer:

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.

Step-by-step explanation:

Given:

Geode shaped approximately like a cylinder. such that

Height = h = 26 feet

Diameter = d = 5.6 feet

$Radius = r =\dfrac{d}{2}=\dfrac{5.6}{2}=2.8\ feet$

To Find:

volume of the geode = ?

Solution:

Geode shaped approximately like a cylinder,

So, Volume of Cylinder is given by,

$\textrm{Volume of Cylinder}=\pi r^{2}h$

Where,

Height = h

Radius = r

pi = 3.14

Substituting the values we get

$\textrm{Volume of Cylinder}=3.14\times 2.8^{2}\times 26=640.05\approx 640.1\ feet^{3}$

Therefore,

The volume of the geode, rounded to the nearest tenth is 640.1 feet³.