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cluponka [151]
3 years ago
6

What is 392 times 207

Mathematics
2 answers:
fgiga [73]3 years ago
7 0

Answer:

81144

Step-by-step explanation:

Free_Kalibri [48]3 years ago
7 0

Answer:

81144

Step-by-step explanation:

392*7 = 2744

392*00 = 0000

392*200 = 78400

78400+0000+2744 = 81144

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A ball is thrown from an initial height of 3 feet with an initial upward velocity of 28 ft/s. The ball's height h (in feet) afte
dimaraw [331]

The value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

Given that the height of the ball at time t is given by the function,

h(t) = 3+ 28t -16t^2

where t is in seconds and h is in feet.

Now, the height of the ball is given to be 11 feet, therefore, substituting the value of h in the function as 11,

h(t) = 3+ 28t -16t^2\\\\11 = 3+ 28t -16t^2\\\\-16t^2 + 28t +3 -11 = 0\\\\-16t^2 + 28t -8 = 0

Now, solving the given quadratic equation, we will get,

x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-(28)\pm \sqrt{(28)^2-4(-16)(-8)}}{2(-16)}\\\\t= 0.36\ or\ 1.39

Hence, the value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

Learn more about Quadratic Equations:

brainly.com/question/2263981

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7 0
2 years ago
Transform Linear. A2. Q1
belka [17]
That's correct
answer is a
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8 0
3 years ago
A quantity, t, varies inversely with a quantity, r. If t = 6, then r = 5.
soldier1979 [14.2K]

Answer:

Step any explanation:

t & 1/r

t = k/r

When t =6 and r = 5

k = tr

k = 6×5

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5 0
3 years ago
1. Which example shows the zero product
aniked [119]

Answer:

The answer is C.....im pretty sure I took the test

Step-by-step explanation:

8 0
2 years ago
I dont understand this, can i get some help please
Ray Of Light [21]

When we want to find the roots of a one-variable function, we look for where its graph intersects the x-axis. In this case, the graph intersects the x-axis at x=1.

The vertex of a parabola is the highest or lowest point on it, depending on whether the leading coefficient of the quadratic function is negative or positive. In this case, we see that the lowest point is (1,0).

For the y-intercept, just look for where the graph intersects the y-axis; in this case, that point is (0,1).

Using this information, the vertex-form equation of the parabola is y=1\cdot(x-1)^2+0, so the factors are two copies of x-1. In this case, the value of a in the equation y=a(x-h)^2+k was conveniently 1; if that's not the case, you'll want to plug in x=0 to solve for the value of a that gives the correct y-intercept.

Does that help clear things up?

3 0
3 years ago
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