Using the t-distribution, as we have the standard deviation for the sample, it is found that the 90% confidence interval is (246.6, 282.8).
<h3>What is a t-distribution confidence interval?</h3>
The confidence interval is:
In which:
- is the sample mean.
- s is the standard deviation for the sample.
The critical value, using a t-distribution calculator, for a two-tailed <u>90% confidence interval</u>, with 16 - 1 = 15 df, is t = 1.7531.
Researching the problem on the internet, the standard deviation was of 42.1 mg/dL, hence the parameters are as follows:
Thus, the bounds of the interval are given by:
The 90% confidence interval is (246.6, 282.8).
More can be learned about the t-distribution at brainly.com/question/16162795
Answer:
See below
Step-by-step explanation:
<u>Given numbers:</u>
- 5.91E10
- 0.0000734
- 2.66 x 10^-3
- 641,000,000,000
<u>Standard notation:</u>
<u>Scientific Notation:</u>
Answer: 50 words per minute
Step-by-step explanation:
<u>250</u> <em>words</em> per <u>5</u> <em>minutes</em> <em>DIVIDE BOTH NUMBERS BY 5</em>
50 words per 1 minute
3/4 lb and used 1/3 of it so we have
3/4*1/3=.25 or 1/4lb used
hope this helps! any questions please just ask! Thank you so much!