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Blababa [14]
2 years ago
6

I need help on these 2 questions, please and thank you!

Mathematics
1 answer:
VikaD [51]2 years ago
5 0

Answer:

1.1 : C - x^2 + x - 2

1.2 : A - 4a^2 - 6b^2 + 12

Step-by-step explanation:

When we have the expression p(x) - q(x), we can substitute those functions in:

(x^2 + 2x - 5) - (x - 3)

We can distribute:

x^2 + 2x - 5 - x + 3

and then combine like terms(2x & -x, -5 & 3)

x^2 + x - 2

This is the same as C.

We can start by distributing:

a^2 - 2b^2 + 3 - 4b^2 + 5 + 3a^2 + 4

Now, we can combine all the a^2 terms(a^2 & 3a^2):

4a^2 - 2b^2 + 3 - 4b^2 + 5 + 4

Then, we can combine the b^2 terms(-2b^2 & -4b^2):

4a^2 - 6b^2 + 3 + 4 + 5

and lastly, all the constants:

4a^2 - 6b^2 + 12

This aligns with option A

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