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rjkz [21]
4 years ago
12

Triangle XYZ is shown on the coordinate plane below:

Mathematics
2 answers:
Tom [10]4 years ago
7 0
Answer: option d. (1, 5)

Explanation:

1) The coordinates of X are (1, -3)

2) When you reflect over a line parallel to the y-axis the x-coordinate does not change, so the x-coordinate of X' is 1.

3) The vertical distance between the point X (1, - 3) and the line y = 1 is 1 - (-3) = 1 + 3 = 4.

4) The vertical distance of the point X' has to ve the same, 4, and the point X' will be 4 units over the line y = 1. That leads to y = 1 + 4 = 5.

So the y-coordinate of the point X' is 5.

5) Conclusion the coordinates of the point X' are x = 1, y = 5, i.e.point (1,5)
Naddik [55]4 years ago
3 0

Answer:

the answer is D. (1,5)

Step-by-step explanation:

I just recently took this exam on FLVS and this is the correct answer, for a better explanation look at the other answer :0

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3 years ago
Read 2 more answers
Classify the system of equations. 2x + y - 3 = 0 x + y - 1 = 0
natta225 [31]
Solve the following system:
{-3 + 2 x + y = 0 | (equation 1)
{-1 + x + y = 0 | (equation 2)

Express the system in standard form:
{2 x + y = 3 | (equation 1)
{x + y = 1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:
{2 x + y = 3 | (equation 1)
{0 x+y/2 = (-1)/2 | (equation 2)

Multiply equation 2 by 2:
{2 x + y = 3 | (equation 1)
{0 x+y = -1 | (equation 2)

Subtract equation 2 from equation 1:
{2 x+0 y = 4 | (equation 1)
{0 x+y = -1 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 2 | (equation 1)
{0 x+y = -1 | (equation 2)

Collect results:
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Archy [21]
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hope this helps!

make me brainliest please if possible :)
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