3 years ago

Which statement about this system of equations is true?

1 answer:

Lunna [17]3 years ago

8 0

Parallel lines have no solution

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tamaranim1 [39]

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$a_{n}=16a_{n-1}$

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salantis [7]

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levacccp [35]

Es x2 o 2x ? Porque con x2 no se podrá resolver, tendría que ser 2x

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2 years ago

Likurg_2 [28]

Answer:

$\textbf{J. }\dfrac{1}{x^2-x}$

Step-by-step explanation:

Factor the denominator and cancel the common factor.

$\dfrac{x+1}{x^3-x}=\dfrac{x+1}{x(x^2-1)}=\dfrac{x+1}{x(x-1)(x+1)}=\dfrac{1}{x(x-1)}\\\\=\boxed{\dfrac{1}{x^2-x}}$

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2 years ago