2D-a^2=2
2(a√2) -a^2=2
a^2-2√2*a+2=0
2a= 2√2 + √(8-4*2) = 2√2
hence, perimeter = 4a = 2*2a=2*2√2 = 4√2
Add or subtract 360 degrees to find a coterminous angle. Since the questions wants you to find one between 0-360, you should subtract 360.
453-360=93 degrees
Join the center of the hexagon with the 2 base angles.
An equilateral triangle, with side length x, is formed.
(remark: a regular hexagon is made up of 6 equilateral triangles with equal length)
The height

forms 2 congruent right triangles with :
hypotenuse= x, side_1=x/2, and side_2=

.
From the pythagorean theorem we have:




thus, x=4.
The area of the triangle is 1/2 * 4 *

=6.93 (mm squared)
The area of the hexagon is 6* the area of the triangle = 42 (mm squared)
Answer: a. 42 (mm squared)
Answer:
5.4
Answer: The value of x rounded to the nearest tenth is 5.4.
Step-by-step explanation: