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gladu [14]
3 years ago
11

Perimeter is a square clock is 16 6/9 inches. Perimeter of a rectangular clock is 16 16/18 inches. Write an inequality comparing

the two perimeters.
Mathematics
1 answer:
worty [1.4K]3 years ago
4 0
<span>16 6/9 inches < 16 16/18 inches or Perimeter of square clock < Perimeter of rectangular clock First we would put convert the perimeter fractions into equivalent terms. So for the square clock, 16 6/9 inches becomes 16 12/18 inches (multiplying the fraction by 2/2). Now it is obvious that that the square clock at 16 12/18 inches has a smaller perimeter than the rectangular clock with a perimeter of 16 16/18 inches.</span>
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natka813 [3]

Answer:

A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be computed from a sample of size 100 drawn from the same population. Choose the best answer to fill in the blank: The interval from the sample of size 400 will be approximately _______as the interval from the sample of size 100.

6 0
3 years ago
3 1/2 X 1 2/3 =<br> what is it?????
puteri [66]

Answer:

5 \frac{5}{6}

Step-by-step explanation:

3 \frac{1}{2}  \times 1  \frac{2}{3}  \\  = 5 \ \frac{5}{6}

6 0
3 years ago
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What is the area of a sheet of binder paper? (Binder paper is 8 1/2 inches by 11 inches.) 88 inches 88 1/2 in2 93 1/2 in2 94 in2
hichkok12 [17]

Answer:

93 1/2 in^2.

Step-by-step explanation:

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=  187/2

=  93 1/2 in^2.

4 0
3 years ago
I'm Sure no one will see or answer this correctly like always...
timurjin [86]
The answer is d.
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7 0
3 years ago
Rationalise the denominator of: (√3 + √2)/(√3-√2) = ?<br>​
krok68 [10]

Step-by-step explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

(√3+√2)/(√3-√2)

<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>

<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>

<h3><u>Solution</u><u>:</u><u>-</u></h3>

We have,

(√3+√2)/(√3-√2)

The denominator = √3-√2

The Rationalising factor of √3-√2 is √3+√2

On Rationalising the denominator then

=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]

=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]

=>(√3+√2)²/[(√3-√2)(√3+√2)]

=> (√3+√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3+√2)²/(3-2)

=> (√3-√2)²/1

=> (√3+√2)²

=> (√3)²+2(√3)(√2)+(√2)²

Since , (a+b)² = a²+2ab+b²

Where , a = √3 and b = √2

=> 3+2√6+2

=> 5+2√6

<h3><u>Answer:-</u></h3>

The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.

<h3><u>Used formulae:-</u></h3>

→ (a+b)² = a²+2ab+b²

→ (a-b)² = a²-2ab+b²

→ (a+b)(a-b) = a²-b²

→ The Rationalising factor of √a-√b is √a+√b

8 0
2 years ago
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