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3 years ago

15

Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money di

d he have at first?

2 answers:

elena-s [515]3 years ago

7 0

Let, his original money = x
It would be: x * 1/2 = 120
x = 120 * 2
x = 240

In short, Your Answer would be $240

Hope this helps!

Kobotan [32]3 years ago

5 0

The answer is $320...

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(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

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<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

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<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

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