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Naily [24]
3 years ago
14

Simplify the expression. -2(7-12)

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0
-2(7-12)=
-2(-5)=
10 = Answer
mylen [45]3 years ago
6 0
Answer: 10
7 minus 12 is negative 5. Negative 2 times negative 5 is 10. 
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Pls help me with this
katovenus [111]

Answer:

5.85

Step-by-step explanation:

100%-> 6.50

100%-10% = 90 %

90%-> 6.50/100 x 90

           =5.85

8 0
3 years ago
Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of th
Genrish500 [490]

N, N+2, and N + 4 are the ages


(N + 4) - (2N) = (N + 2) -24


4 - N = N - 22


2N = 26

N = 13

The brothers are 13, 15, and 17 years old.

HOPE THIS HELPS!!

PLEASE GIVE ME BRAINLIEST!!

6 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
456+213 using the break apart strategy
GalinKa [24]
Fist break up each number in the hundreds column add the tens and the ones then add the hundreds to the previous answer
4 0
3 years ago
Daniel paid interest of 1,020 in 5years at12%per annum on a loan. Hw much did he borrow
Marat540 [252]
I = Prt
I=1020
r=0.12 (12% converted to decimal by dividing by 100)
t=5
1020=P(0.12)(5)
1020=P(0.6)
P=1700
5 0
3 years ago
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