Answer:
the first one
Step-by-step explanation:
Answer:
11 1/4 or 45/5
Step-by-step explanation:
just multiply 5 * 2 1/4
And thats ur answer
Answer:
510g H2S
Step-by-step explanation:
En esta pregunta, se nos pide calcular la masa de H2S emitida cuando 5 moles de sulfuro de níquel reaccionan completamente con el agua.
De la ecuación equilibrada, podemos ver que 1 mol de sulfuro de níquel produjo 3 moles de sulfuro de hidrógeno Por lo tanto, 5 moles de sulfuro de níquel producirán = 5 * 3 moles = 15 moles de sulfuro de hidrógeno
Matemáticamente, la masa se puede calcular multiplicando el número de moles por masa molar La masa molar de H2S es 2 (1) + 32 = 34 g / mol La masa en gramos así producida = 15 mol * 34g / mol = 510g
Let x(t) = the length of a side of the square (cm) at time t (s).
The rate of change of x is given as
The area (cm²) at time t is
A = x²
The rate of change of the area with respect to time is
When A = 9 cm², then x = √9 = 3cm. Hence obtain
Answer: 12 cm²/s
Answer:
The least amount of time (in hours) both pumps need to be open is 3 hours.
Step-by-step explanation:
According to the Question,
- Given That, A pool has two inlet pumps A and B. If pump A alone is open, it takes 12 hours to fill the pool with water. If pump B alone is open, it takes 18 hours to fill the pool with water.
Let the Capacity of the Pool is 36Litre.
- Thus, If pump A alone is open, it takes 12 hours to fill the pool with water. thus the Efficiency of Pipe A is 3 ltr/hour.
- And, If pump B alone is open, it takes 18 hours to fill the pool with water. thus the Efficiency of Pipe B is 2 ltr/hour.
If the pool needs to be filled in 10 hours the least amount of time (in hours) both pumps need to be open is 3 hours.
Note:- if 3 hour both pipe open so 3 x (5) = 15 ltr Pool is Filled.
Now For Remaining 7 hour Pipe A with Efficiency 3 ltr/hour is open alone to fill the pool Remaining 7 x 3 = 21 ltr . Total 21+15 = 36ltr .
