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2 years ago

When the smaller of two consecutive integers is added to fivefive times the larger, the result is 5959. find the integers?

Mathematics

1 answer:

dangina [55]2 years ago

5 0

X + 5(x + 1) = 59
6x + 5 = 59
6x = 54
x = 9

The 2 integers are 9 and 10

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$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

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$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

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$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

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2 years ago

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Oksi-84 [34.3K]

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Step-by-step explanation:

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Paraphin [41]

Answer:

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In right triangle ACB, $CD\perp AB$

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2 years ago

When the smaller of two consecutive integers is added to fivefive times the​ larger, the result is 5959. find the integers?

When the smaller of two consecutive integers is added to fivefive times the larger, the result is 5959. find the integers?