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3 years ago

A rectangular room is four times as long as it is wide, and its perimeter is 70 meters. Find the width of the room.

2 answers:

8 0

<span>W=3/4L
P=2L=2W
70=2L+2(3/4L)
70=2L+6L/4
70=2L+1.5L
70=3.5L
L=70/3.5
L=20 FT. ANS. FOR THE LENGTH.
W=4/4*20=15 ANS. FOR THE WIDTH

i think. </span>

Roman55 [17]3 years ago

4 0

2(4w) + 2w = 70
8w + 2w = 70
10w = 70
W= 7 m

Again, you just have to learn to make the equations. :)

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Find the slope of the line that contains the following ordered pairs (4,2) (7,6.5)

klio [65]

Answer:

4.5/3 or 1.5

Step-by-step explanation:

slope formula: (y2-y1)/(x2-x1)

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3 years ago

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3 years ago

What is 32/23 as a decimal rounded to the nearest hundredth<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B32%7D%7B23%7D%20"

Softa [21]

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4 years ago

Emma is making a scale drawing of her farm using the scale 1 cm = 2.5 ft. In the drawing, she drew a well with a diameter of 0.5

xz_007 [3.2K]

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3 years ago

Read 2 more answers

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

8 0

3 years ago