You would do 10x10x10x10x10, so it would be 100,000. So you're correct, nice job!
Answer:
I think it is C if you have a base nuber of 7 that is at least halfway acros it it can not be over 100
Step-by-step explanation:
The number of weeks required to have enough money in account to buy computer is 12
<em><u>Solution:</u></em>
Given that Maya has $210 in a savings account for a new computer the computer cost $537.15 including sales tax
At the end of each week she deposits $27 into the account
<em><u>To find: number of weeks required to have enough money in the account for the computer</u></em>
Total cost of computer = $ 537.15
Amount in savings account = $ 210
Let "a" be the number of weeks required to have enough money in account to buy computer
Each week she deposits $27 into the account
<em><u>So we can we frame a equation as:</u></em>
total cost of computer = Amount in savings account + (number of weeks x 27)
Thus number of weeks required is 12 approximately
To solve this problem you must apply the proccedure shown below:
1. You have the following quadratic equation given in the problem above:
2. You must factor out the greatest common factor, which is: :
3. It has the form of a Perfect square trinomial then, you can write it as , where .
4. Therefore, you have that the answer is: