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3 years ago

Which product of nuclear decay has mass but no charge?

1 answer:

4 0

Alpha particles have a charge of +2 and a mass of 4
Gamma rays have a charge of 0 and a mass of 0
Neutrons have a charge of 0 and a mass of 1
Beta positrons have a charge of +1 and a mass of 0

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How do the orbits of a comet and earth compare?

TiliK225 [7]

Comets are balls of ice and dust in orbit around the Sun. The orbits of comets are different from those of planets - they are elliptical. A comet's orbit takes it very close to the Sun and then far away again.

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3 years ago

6. Explain a situation in which elastic potential energy could be transformed into kinetic energy.

dsp73

Answer:

When you pull a rubber band there is elastic potential energy stored in the rubber band but once you let go of either side the EPE turns into Kinetic Energy.

6 0

2 years ago

How many moles are in 50 g of CO2

murzikaleks [220]

Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

8 0

2 years ago

Elimination of the pharmaceutical IV antibiotic gentamicin follows first-order kinetics. If the half-life of gentamicin is 1.5 h

Genrish500 [490]

Explanation:

The given data is:

The half-life of gentamicin is 1.5 hrs.

The reaction follows first-order kinetics.

The initial concentration of the reactants is 8.4 x 10-5 M.

The concentration of reactant after 8 hrs can be calculated as shown below:

The formula of the half-life of the first-order reaction is:

$k=\frac{0.693}{t_1_/_2}$

Where k = rate constant

t1/2=half-life

So, the rate constant k value is:

$k=\frac{0.693}{1.5 hrs}$

The expression for the rate constant is :

$k=\frac{2.303}{t} log \frac{initial concentration}{concentration after time "t"}$

Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:

$\frac{0.693}{1.5 hrs} =\frac{2.303}{8 hrs} x log \frac{8.4x10^-^5}{y} \\ log \frac{8.4x10^-^5}{y} =1.604\\\frac{8.4x10^-^5}{y}=10^1^.^6^0^4\\\frac{8.4x10^-^5}{y}=40.18\\y=\frac{8.4x10^-^5}{40.18} \\=>y=2.09x10^-^6$

Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.

5 0

3 years ago

18 grams<br> 4 kilograms<br> 8 kilograms

Rina8888 [55]

Answer:

1 18 grams

2 500g

4 960 grams

5 7 kilograms

5 0

3 years ago