A Cell with few energy needs would most likely contain a small number of Mitochondria.
- All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
- They transform glucose into ATP, a chemical with a huge energy storage capacity.
- Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
- Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
- Vacuoles are typically tiny and aid in the sequestration of waste.
- The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.
Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.
Learn more about cell organelles here:
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Answer:
[HF]₀ = 0.125M
Explanation:
NaOH + HF => NaF + H₂O
Adding 20ml of 0.200M NaOH into 25ml of HF solution neutralizes 0.004 mole of HF leaving 0.004 mole NaF in 0.045L with 0.001M H⁺ at pH = 3. This is 0.089M NaF and 0.001M HF remaining.
=> 45ml of solution with pH = 3 and contains 0.089M NaF from titration becomes a common ion problem.
HF ⇄ H⁺ + F⁻
C(eq) [HF] 10⁻³M 0.089M (<= soln after adding 20ml 0.200M NaOH)
Ka = [H⁺][F⁻]/[HF]₀ => [HF]₀ = [H⁺][F⁻]/Ka
[HF]₀ = (0.001)(0.089)/(7.1 x 10⁻⁴) M = 0.125M
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Trick question: you just stated everything in the beakers.
Answer:
The right answer is "![[Na^+]=5.57 \ ppm](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D5.57%20%5C%20ppm)
".
Explanation:
The given values are:
According to the question,
The concentration of standard will be:
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Coffee after dilution,
⇒ 
or,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
hence,
In unknown sample, the concentration of coffee will be:
= 
= 
= 
