How many orbitals are completely filled in an atom whose electron configuration is 1s^2 2s^2 2p^6 3s^1?

Chemistry

2 answers:

Nimfa-mama [501]3 years ago

6 0

Hey there!:

The 1s, 2s and 2p subshells are completely filled (a maximum of two electrons go into the 1s subshell and a maximum of two electrons go into the 2s subshell. The 2p subshell includes 3 orbitals, with 2 electrons maximum per orbital). The 3s subshell has only one of a maximum of two electrons.

Hope that helps!

nataly862011 [7]3 years ago

3 0

The number of orbitals that are completely full is 5.

The reason you may have thought it was 3 is because you're confusing orbitals with subshells.

In this electron configuration, the sub shells are: 1s^2, 2s^2, 2p^6, 3s^1

So, we have four sub shells.

Each sub shell consists of a specific number of orbitals. s subshells have one orbital, p subshells have three orbitals, d subshells have five orbitals, and f subshells have seven orbitals. Knowing this, we can look back at the electron configuration we were given and determine how many orbitals are filled.

1s^2 has one orbital, 2s^2 has one orbital, 2p^6 has three orbitals, and 3s^1 has one orbital. The first three subshells are completely full, so a total of five orbitals are full.

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If you dilute a solution what is the only thing about the solution that does NOT change?

lukranit [14]

Taking into account the definition of dilution, moles of solute (option C) is the only thing about the solution that does NOT change.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Summary</h3>

In summary, moles of solute (option C) is the only thing about the solution that does NOT change.

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8 0

1 year ago

Which of these statements would be true if the water molecule was linear instead of bent? Check all that apply.

Katen [24]

If the water molecule was linear instead of bent the water would no longer produce hydrogen bonds.

Explanation:

Yes, If the water molecule was linear instead of bent the water would no longer produce hydrogen bonds.
The water would no longer generate hydrogen bonds.
It will lose its polar features and nearly all of its features will change such as boiling point, water tension and solubility.
It would be more like to gas, rather than liquid.
If the water was in the linear, the water would have all the features and it would produce the hydrogen bonds.

4 0

3 years ago

Read 2 more answers

the ph of a solution of HCl in water is found to be 2.50. what volume of water would you add to 1.00L of this solution to raise

morpeh [17]

Answer:

To raise the pH of the solution to 3.10 we have to add 2.34 L of water.

Explanation:

Given that the pH of the solution of HCl in water is 2.5. Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. $[H^+]$ ions contribute to a solution’s acidic nature and $[OH^-]$ contribute to a solution’s basic nature.