6y+y(4)
7y(4)
y=4/7
Youre welcome
we know that
1 ft--------> is equals to 12 in
the ramp is 12 inches tall----------> 1 ft tall
A ramp measures------------------> 6 ft long
applying the Pythagorean theorem
c²=a²+b²
where
c-----> 6 ft long
a----> horizontal distance
b-----> 1 ft tall
a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft
the answer is
5.92 ft
Answer:
16302.9432 ft
Step-by-step explanation:
P = 2L + 2W
Where P is the perimeter, L is the length and W is the width
P = 2(1080√30) + 2(500√20) = 16302.9432 ft
7 x 4 = 28
To get 33 is you add 28 and 5 to get 33
Answer:
<em>908360.67 lb-ft</em>
<em></em>
Step-by-step explanation:
height of tank= 6 ft
diameter of the tank = 4 ft
density of water p = 62.4 lbs/ft
A is the cross sectional area of the tank
A = 
where r = diameter/2 = 4/2 = 2 ft
A = 3.142 x
= 12.568 ft^2
work done = force x distance through which force is moved
work = F x d
Force due to the water = pgAh
where g = acceleration due to gravity = 32.174 ft/s^2
Force = 62.4 x 32.174 x 12.568 x 6 = 151393.44 lb
work done = force x distance moved
work = 151393.44 x 6 = <em>908360.67 lb-ft</em>