Find 0.Trigonometry problems.

Mathematics

1 answer:

aivan3 [116]2 years ago

6 0

In the triangle with legs 7 and 9 cm, you can find the length of the hypotenuse by using the Pythagorean theorem. If the hypotenuse is $x$ , then

$7^2+9^2=x^2\implies x=\sqrt{130}$

The other right triangle with leg 6 cm and containing the angle $\theta$ satisfies

$\sin\theta=\dfrac{6\,\rm cm}{\sqrt{130}\,\rm cm}\implies\theta=\sin^{-1}\dfrac6{\sqrt{130}}\approx31.75^\circ$

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In this figure

alina1380 [7]

Answer:

∠y = 62.5°

∠x = 27.5°

Step-by-step explanation:

z is right angle. ∠z = 90°

∠x = ∠y - 35

∠x + ∠y + ∠z = 180 {Angle sum property of triangle}

y - 35 + y + 90 = 180

y + y - 35 + 90 = 180 {Combine like terms}

2y + 55 = 180

2y = 180 -55 {Subtract 55 from both sides}

2y = 125 {Divide both sides by 2}

y = 125 /2

∠y = 62.5°

∠x = 62.5 - 35 = 27.5°

6 0

2 years ago

Angle 1 and angle 3 are ___ angles.

slega [8]

Angles 1 and 3 are vertical lines and because they are vertical, both angles equal each other.

4 0

2 years ago

If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?

katrin [286]

Answer:

$\large\boxed{\dfrac{3(6)-1}{2(6)+1}}$

Step-by-step explanation:

$\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}$