$\bf \stackrel{map}{1~cm}\qquad :\qquad \stackrel{actual}{77~km}\qquad \cfrac{map}{actual}=\cfrac{1}{77}~\hfill \cfrac{\stackrel{map}{3}}{\underset{actual}{a}}=\cfrac{1}{77}\implies 231=a$

4 0

2 years ago

Select the correct answer. What is the y-intercept of f(x) = 3x+2?

pashok25 [27]

Answer:

The y-intercept is (0, 3)

<em>they typed the equation wrong so that's why it's (0, 3)</em>

3 0

2 years ago

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Help me please i don’t get how to point slope this equation please

PSYCHO15rus [73]

Answer:

y-5=3x-15

Step-by-step explanation:

Slope=(5+1)/(-6+8)

=6/2

Equation of line passing throgh point (-6,5):

y-5=3(x-5)

y-5=3x-15

3 0

2 years ago

Select all that apply

Anastaziya [24]

Answer:

<h2>Third option</h2>

$\log _{10}\left(20x^5\right)-1\\$

Step-by-step explanation:

$5\log _{10}\left(x\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\\\\5\log _{10}\left(x\right)=\log _{10}\left(x^5\right)\\\\=\log _{10}\left(x^5\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\\\\\log _{10}\left(x^5\right)+\log _{10}\left(20\right)=\log _{10}\left(20x^5\right)\\\\$

$=\log _{10}\left(x^5\cdot \:20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\\=\log _{10}\left(20x^5\right)-1$

5 0

3 years ago

Read 2 more answers