Id there are 21 girls according to my calculations there would be a heap amount of boys which is 23
Answer: Graphing is the best in this situation
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
i looked up the answers
Answer:
49
Step-by-step explanation:
Let x represent the length and y represent the width of the given rectangle. The perimeter of the rectangle will be:
Perimeter = 2(x + y)
32 = 2(x + y)
16= x + y
This means, the sum of length and width of the rectangle can be 16. Since only whole number side lengths are allowed, following are the possibilities:
- Side Lengths: 15, 1 Area = 15
- Side Lengths: 14, 2 Area = 28
- Side Lengths: 13, 3 Area = 39
- Side Lengths: 12, 4 Area = 48
- Side Lengths: 11, 5 Area = 55
- Side Lengths: 10, 6 Area = 60
- Side Lengths: 9, 7 Area = 63
- Side Lengths: 8, 8 Area = 64
Hence the largest possible value of Area is 64 and the least possible value is 15. The difference is 64 - 15 = 49
The solution to the <span>system of equations graphed above would be the point where they intersects and also when they are represented in an equation, it is the values of x and y that makes the equations correct. It should be the third option. The apparent solution to the lines would be point (1,2).
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