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Sidana [21]
3 years ago
6

A 1.4-µC point charge is placed between the plates of a parallel plate capacitor. The charge experiences a force of 0.59 N. What

is the magnitude σ of the charge density on either plate of the capacitor?
Physics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

\sigma=3.72\times 10^{-6}\ C/m^2

Explanation:

Given that,

Charge, q=1.4\ \mu C=1.4\times 10^{-6}\ C

Force experienced by the charge, F = 0.59 N

We need to find the magnitude of charge density on either plate of the capacitor. Electric field on parallel plate capacitor is given by :

E=\dfrac{\sigma}{\epsilon_o}

E=\dfrac{F}{q}

\dfrac{F}{q}=\dfrac{\sigma}{\epsilon_o}

\sigma=\dfrac{F.\epsilon_o}{q}

\sigma=\dfrac{0.59\times 8.85\times 10^{-12}}{1.4\times 10^{-6}}

\sigma=3.72\times 10^{-6}\ C/m^2

So, the charge density on either plate of the capacitor is 3.72\times 10^{-6}\ C/m^2. Hence, this the required solution.

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