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zalisa [80]
3 years ago
9

Kat driving 55 mph approaching a stop light. It takes her 15 seconds to completley atop at the stop light. what was her accelera

tion?
Physics
1 answer:
tresset_1 [31]3 years ago
4 0
SHAKE THAT ASSS QUEEN YESSS
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A sprinter has a mass of 80 kg and a kinetic energy of 2500 J. What is the sprinter's speed?
nata0808 [166]
Using KE = 1/2mv^2
m = mass (80kg)
v = velocity (?)
KE = kinetic energy (2500J)
2500/((1/2) x (80)) = v^2
Square root the answer to get: 7.91 m/s
3 0
2 years ago
What is the relationship between the force of gravity between two objects in regard to their mass and the distance between them?
Mashcka [7]

Answer:

hi

Explanation:

5 0
3 years ago
Q4. Consider the skier on a slope shown in the figure below. Her mass including equipment is 55.0 kg.
Shkiper50 [21]

Answer:

Part a)

When there is no friction then acceleration is

a = 4.14 m/s^2

Part b)

if there is friction force along the inclined then acceleration is

a = 3.33 m/s^2

Explanation:

Part a)

As we know that the skier is on inclined plane

So here if there is no friction then net force along the inclined plane is given as

F = mg sin\theta

now acceleration of the skier is given as

a = \frac{F}{m}

a = g sin\theta

a = 9.81(sin25)

a = 4.14 m/s^2

Part b)

if there is friction force along the inclined then net force along the inclined plane is given as

F = mg sin\theta - F_f

now acceleration of the skier is given as

a = \frac{F}{m}

a = g sin\theta - \frac{F_f}{m}

a = 9.81(sin25) - \frac{45}{55}

a = 3.33 m/s^2

5 0
4 years ago
When the computer you are working on uses energy it also produces waste energy. What type of energy is this waste energy?
mihalych1998 [28]
i think it is phisical energy
5 0
3 years ago
The boys tried a second experiment. They built a balloon car like the one seen here. As the gas in the balloon is released, the
sukhopar [10]

Answer:

newton's third law of motion

Explanation:

The model of balloon car is example of newton's third law of motion which says that to every action there is always and equal and opposite reaction. As the balloon is inflated and then release the nozzle, the rubber contacts and pushes the air forward out of the nozzle, the air pushes back on the rubber and propelling the balloon forward.

5 0
3 years ago
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