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vagabundo [1.1K]

2 years ago

14

What is the density of an object with a mass of 1.663 g and a volume of 0.2009 mL

2 answers:

bearhunter [10]2 years ago

8 0

1.663g (Mass) ÷ 0.2009mL (Volume) = 8.27775012g/mL
(or 8.2778 if you round to the fourth decimal place)

daser333 [38]2 years ago

7 0

<span>8.278 g/mL The definition of density is mass per volume. So what you need to do is divide the known mass by the known volume. So 1.663 g / 0.2009 mL = 8.27775 g/mL But you also have to keep track of significant figures. Since both 1.663 and 0.2009 have 4 significant figures each, you need to round the result to 4 significant figures. So 8.27775 g/mL = 8.278 g/mL</span>

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4/5(2x 5)−4=1

uysha [10]

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Which of the following statements is incorrect? Group of answer choices The product of wavelength and frequency of electromagnet

morpeh [17]

Answer: Option (b) is the correct.

Explanation:

It is known that energy is directly proportional to frequency.

Mathematically, $E \propto \nu$

or, E = $h \times \nu$ ............ (1)

where, E = energy

h = Plank's constant

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This relation shows that higher is the energy then more will be the frequency of electrmagnetic radiation.

Also, $\nu = \frac{c}{\lambda}$ ......... (2)

where, c = speed of light

$\lambda$ = wavelength

Therefore, substituting value of $\nu$ from equation (2) into equation (1) as follows.

E = $h \times \nu$

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3 years ago

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ANEK [815]

Explanation:

The given data is as follows.

Vapour pressure of pure $CCl_{4}$ = 33.85 Torr

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Therefore, calculate the vapor pressure of $Br_{2}$ as follows.

Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

= 0.050 x 122.36 Torr

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So, vapor pressure of $Br_{2}$ is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

Vapour pressure of $CCl_{4}$ = mole fraction of $CCl_{4}$ x Pressure of $CCl_{4}$

= (1 - 0.050) × 33.85 Torr

= 32.1575 Torr

So, vapor pressure of $CCl_{4}$ is 32.1575 Torr .

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= 6.118 Torr + 32.1575 Torr

= 38.2755 Torr

Therefore, composition of $CCl_{4}$ = $\frac{32.1575 Torr}{38.2755 Torr}$

= 0.8405

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= 0.1598

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