Question

A molecule contains 24.36 g of nitrogen and 62.64g of sliver

Answer 1

Answer:

This molecule is AgN3

Explanation:

Answer 2

Answer:

AgN3

Explanation:

Mass of nitrogen N is given as 24.36 g

Molar mass of nitrogen N= 14 g/mol.

amount of substance in mol of N = mass/molar mass

=24.36 g/ 14 g/mol.

=1.74 mol.

Given mass of silver= 62,64 g.

Molar mass of silver Ag=107.87 g/mol

Number of mols=62.64 g ÷ 107.87 g/mol.

=0.58 mol.

Ratio of number of mol of N and number of mols of Ag = 1.74 mol / 0.58 mol

=3:1

Hence, empirical formula is AgN₃.