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Harman [31]
3 years ago
11

A molecule contains 24.36 g of nitrogen and 62.64g of sliver

Chemistry
2 answers:
Komok [63]3 years ago
5 0

Answer:

This molecule is AgN3

Explanation:

ivolga24 [154]3 years ago
3 0

Answer:

AgN3

Explanation:

Mass of nitrogen N is given as 24.36 g

Molar mass of nitrogen N= 14 g/mol.

amount of substance in mol of N = mass/molar mass

=24.36 g/ 14 g/mol.

=1.74 mol.

Given mass of silver= 62,64 g.

Molar mass of silver Ag=107.87 g/mol

Number of mols=62.64 g ÷ 107.87 g/mol.

=0.58 mol.

Ratio of number of mol of N and number of mols of Ag = 1.74 mol / 0.58 mol

=3:1

Hence, empirical formula is AgN₃.

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Answer:

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Explanation:

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3 years ago
If an atom has an atomic number of 6 and and abdomens mass of 12 how many electrons does it have
Basile [38]
Atomic number refers to the proton number of the atom itself. Number of electrons in an atom (an atom that is not reacted with any other molecules / Just the atom alone), is the same as the number of protons, because each electron has 1 negative charge, and each proton 1 positive charge, where they cancel out on each other to become a neutral charge.

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3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

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3 years ago
2Li + H2SO4=Li2SO4 + H2 How many liters of hydrogen gas, H2 at STP can be produced from 3.0 moles of Li? The molar volume of a g
Gemiola [76]

Answer:

volume of H_2=33.6 litre

Explanation:

Firstly balance the given chemical equation,

2Li + H_2SO_4=Li_2SO_4 + H_2

From the given balance equation it is clearly that,

2 mole of Li gives  1 mole of H2 gas

2 mole Li⇔1 mole H_2

1 mole Li⇔0.5 mole H_2

3 mole Li⇔1.5 mole H_2

hence

3 mole of Li will give 1.5 mole H2 gas

therefore volume of gas produced from 3 mole Li at STP = 1.5\times22.4 \frac{L}{mol}

volume of H2=33.6 litre

7 0
3 years ago
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