Answer:
29 mL
Explanation:
<h3>Equation</h3>
The question needs us to find the volume of the liquid. The equation for volume using density and mass is:
Volume = Mass / Density
<h3>Solve</h3>
We can substitute the given values for density and mass into the equation:
<h3>Additional Comments</h3>
The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.
Below are the significant figure rules:
Nonzero digits will always be significant (eg. 54 --> 2 significant figures)
Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)
Zeroes between two nonzero digits will always be significant (eg. 504 --> 3 significant figures)
Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)
4 mol / 205g H2O = 4/.205 = 19.5 mol/kg boiling point = 100 + 19.5 • 0.51 = 109 ºC
Answer:
Exothermic reaction for the HCl, endothermic reaction for the water
Explanation:
Heat was lost by HCl as its temperature lowered, so it was an exothermic reaction for the HCL.
Heat was gained by water as its temperature increased, so it was an endothermic reaction for the water.
m = Mass of water = 100 g
c = Specific heat of water = 
= Change in temperature of water = 
Heat is given by
Heat gained by water is .
B. Carbon dioxide bexause it is 96.5%
From the information given, the total volume of rubbing alcohol is 88.2 ml
68.6 % of this volume is isopropanol.
We will assume 88.2 ml represents 100% volume, so the volume of water will be 31.4 %
The volume of isopropanol is
68.6/100 x 88.2 → 0.686 × 88.2 = 60.505 ml
The volume of isopropanol is 60.5 ml.
Volume of water will be 88.20 - 60.5 = 27.7 ml
(27.7 / 88.2 × 100 = 31.4% )
Adding 60.5 ml of isopropanol to 27.7 ml of water to make up 88.2 ml will give 68.6 % v/v isopropanol to water solution.
