This question involves the concept of the scalar product.
The magnitude of the scalar product will be "0".
<h3>SCALAR PRODUCT</h3>
The scalar product, also known as the dot product of the two vectors is given by the following formula:
where,
- A.B = Scalar product = ?
- |A| = Mangnitude of vector A = 1 unit
- |B| = Magnitude of Vector B = 1 unit
- θ = Angle between vectors = 90°
Therefore,
A.B = 0
Learn more about scalar product here:
brainly.com/question/6849226
The maximum diffraction order seen is 3.
<h3>What is the maximum diffraction order seen?</h3>
We know that the maximum angle of diffraction Q_m of the furthest bright fringe < Q = 90 degrees.
Here we need to compute the nth bright fringe for which is approximated to 90 degrees.
The angle of nth bright fringe is given by;
sin(Q_m) = n(λ)N
Approximating Q_m ≈ 90 degrees.
sin (90) = nλN
n = sin (90) / (λN)
n = 1 / ((580 x 10⁻⁶)500)
n = 3.5 orders
Since, we knew that Q_m < 90 degrees, we will choose n = 3 as the maximum number of orders.
Thus, the maximum diffraction order seen is 3.
Learn more about maximum diffraction here: brainly.com/question/14703089
#SPJ4
Answer:
4.9 m/s
Explanation:
Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the ball in this problem,
u = 0 (it starts from rest)
is the acceleration
s = 3 m is the distance covered
Solving for v,
The strength of the gravitational field is given by:
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
And now we can use the previous equation to calculate the field strength at that altitude:
And we can see this value is a bit less than the gravitational strength at the surface, which is
.
