Answer:
K = 25351. 69 N / m
Explanation:
Given : Fk = 515 N , v = 1.8 m /s , d = 5.0 m , β = 22.0 ° , m = 150 kg
Using the work done by all forces at initial and the end can determine the constant of the spring
Ws + We - Fk = Em - Ef
- ¹/₂ * K * x² + m*g*h - F*d = 0 - ¹/₂ * m * v²
Also the round motion part
K* x = F + We
K * x = F + m*g*h
Replacing numeric to equal the equations and find the constant
¹/₂ * K * x² = 150*9.8* 5* sin (22°) - 5150* 5 + ¹/₂*150*(1.8m/s)²
K * x² = 421.358
Now use the other equation
K * x = 515 + 150*9.8* sin(22°)
K * x = 3268.35
Both equation give x' as a
x = 0.1289 m now using in any equation can find K
K = 25351. 69 N / m
Answer:
1. a) Draw a line towards the right side from the engine
b) This force pushes the boat forward and helps it accelerate further
2. a) Fixed volume for both solid and liquid
Compressible for only solid
Fixed shape is also for only Solid
b) The answer is 'c'
c) Solids, because they have their particles closely packed therefore they can be compressed (not so sure bout this answer)
Answer:
k = 45.95 N/m
Explanation:
First, we will find the launch speed of the ball by using the formula for the horizontal range of the projectile.
where,
Vo = Launch Speed = ?
R = Horizontal Range = 5.3 m
θ = Launch Angle = 35°
Therefore,
v₀² = 55.33 m²/s²
Now, we know that the kinetic energy gain of ball is equal to the potential energy stored by spring:
where,
k = spring constant = ?
x = compression = 17 cm = 0.17 m
m = mass of ball = 24 g = 0.024 kg
Therefore,
<u>k = 45.95 N/m</u>
a). for velocity, you must have a number, a unit, and a direction.
Yes. This one isn't bad. The 'number' and the 'unit' are the speed.
b). the si units for velocity are miles per hour.
No. That's silly.
'miles' is not an SI unit, and 'miles per hour'
is only a speed, not a velocity.
c). the symbol for velocity is .
You can use any symbol you want for velocity, as long as
you make its meaning very clear, so that everybody knows
what symbol you're using for velocity.
But this choice-c is still wrong, because either it's incomplete,
or else it's using 'space' for velocity, which is a very poor symbol.
d). to calculate velocity, divide the displacement by time.
Yes, that's OK, but you have to remember that the displacement
has a direction, and so does the velocity.
