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marta [7]
1 year ago
5

what are the main morphological types of galaxies, and what is the difference in their rotation patterns?

Physics
1 answer:
ankoles [38]1 year ago
3 0

The main morphological types of galaxies are elliptical, spiral, and irregular.

Based on their morphology , galaxies have been classified into 3 types namely elliptical, spiral, and irregular.

These galaxies have various sizes and shapes ranging from dwarf galaxies to giant galaxies.

Elliptical Galaxy:

  • The shape of it is generally circular
  • These are the largest among all the types of galaxies because according to astronomers, it is formed by the merger of other small galaxies.
  • Their rotational pattern is symmetric.

Spiral Galaxy:

  • A spiral galaxy consists of a bright nucleus surrounded by a thin outer disk forming a spiral shape.
  • This type of galaxy is the most common in our universe.
  • It is divided into three classes: Spiral a, Spiral b, and Spiral c.
  • Their rotational pattern has circular symmetry.

Irregular Galaxy:

  • These types of galaxies have no central nucleus and irregular arms which are bluish.
  • They don’t have any rotational symmetry.

To know more about "galaxies", refer to the following link:

brainly.com/question/24836631?referrer=searchResults

#SPJ4

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A 0.500-nm x-ray photon is deected through 134 in a Compton scattering event. At what angle (with respect to the incident beam)
natita [175]

Answer:

The angle of recoil electron with respect to incident beam of photon is 22.90°.

Explanation:

Compton Scattering is the process of scattering of X-rays by a charge particle like electron.

The angle of the recoiling electron with respect to the incident beam is determine by the relation :

\cot\phi = (1+\frac{hf}{m_{e}c^{2}  })\tan\frac{\theta }{2}      ....(1)

Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant, m_{e} is mass of electron, c is speed of light and f is the frequency of the x-ray photon.

We know that, f = c/λ      ......(2)

Here λ is wavelength of x-ray photon.

Rearrange equation (1) with the help of equation (1) in terms of  λ .

\cot\phi = (1+\frac{h}{m_{e}c\lambda  })\tan\frac{\theta }{2}

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for m_{e}, 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ  and 134° for θ in the above equation.

\cot\phi = (1+\frac{6.6\times10^{-34} }{9.1\times10^{-31}\times3\times10^{8}\times0.5\times10^{-9}  })\tan\frac{134 }{2}

\cot\phi=2.37

\phi = 22.90°

8 0
3 years ago
How far away is mars?
Elanso [62]

Answer:

about: 110.14 million mi

Explanation:

the distance to Mars from Earth is 140 million miles (225 million kilometers).But, distance to Mars from Earth is constantly changing.

Hope that was helpful.Thank you!!!

3 0
3 years ago
Read 2 more answers
A block of mass 9.2kg rests on a slope an angle of 26.9∘ relative to the horizontal. What is the size of the contact force norma
Olegator [25]

Answer:

80.4 N

Explanation:

As the block is at rest on the slope, it means that all the forces acting on it are balanced.

We are only interested in the forces that act on the block along the direction perpendicular to the slope. Along this direction, we have two forces acting on the block:

- The normal reaction N (contact force), upward

- The component of the weight of the block, mg cos \theta, downward, where m is the mass of the block, g is the gravitational acceleration and \theta is the angle of the incline

Since the block is in equilibrium along this direction, the two forces must balance each other, so they must be equal in magnitude:

N=mg cos \theta

And by substituting the numbers into the equation, we find the size of the contact force normal to the slope:

N=(9.2 kg)(9.8 m/s^2)(cos 26.9^{\circ})=80.4 N

6 0
3 years ago
how should the table be changed to correctly distinguish between mechanical and electromagnetic waves?
goblinko [34]
Sound waves and light waves need to change
3 0
1 year ago
A bolt is to be tightened with a torque of 7.0 N · m. If you have a wrench that is 0.55 m long, what is the least amount of forc
kodGreya [7K]

To solve this problem we will apply the given concept for torque which explains the relationship between the force applied and the distance to a given point. Mathematically this relationship is given as

\tau = F*d \rightarrow F = \frac{\tau}{d}

Where,

\tau = Torque

F = Force

d = Distance

Our values are given as,

\tau = 7.0Nm , d = 0.55m

Therefore replacing we have that the force is

F = \frac{7}{0.55}

F = 12.72N

Therefore the least amount of force that you must exert is 12.72N

4 0
2 years ago
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